Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie,
"ace"
is a subsequence of "abcde"
while "aec"
is not).
Example 1:
s =
s =
"abc"
, t = "ahbgdc"
Return
true
.
Example 2:
s =
s =
"axc"
, t = "ahbgdc"
Return
false
.
Follow up:
If there are lots of incoming S, say S1, S2, ... , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?
If there are lots of incoming S, say S1, S2, ... , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?
Go through the string and whenever pass all chars that don't match. In the end a subsequence of the string should reach to the end.
public boolean isSubsequence(String s, String t) { int lenS = s.length(), lenT = t.length(); if (lenS == 0) { return true; } if (lenS > lenT) { return false; } int posS = 0, posT = 0; while (posS < lenS && posT < lenT) { while (posT < t.length() && t.charAt(posT) != s.charAt(posS)) { posT++; } posS++; posT++; } return posS == lenS; }
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